I can not understand that I'm trying to recreate the "complex" C ++ class and those tasks.
For example: using real (), image (), eb ()
parameters etc. const complex & amp; Obj
. So I thought that if you pass an object from your reference then it is not copied and saves a little memory and it uses further const
to prevent that object from being messed up is. Am i right So I thought I could make my works as well, but why do const
need those functions with parameters with const
? Here's what I found:
class MyComplex {Private: double real; Double image; Public: My Complex (); My Complex (Int real); MyComplex (integer, real, integer); Double met real (); Double getImag (); Zero set real (int real); Zero set imag (int image); Friend's cut double real (Costmemplex & OBJ); Buddy's Constant Double Image (Constmangplux and OBJ); Friend's Cunt Double Abs (Kont Micromax & OBJ); Friend Kant Double ARG (Cut Microplocks & OBJ); Friend Const Double Harm (Kont Micromax & OBJ); Friend const std :: string conj (const MyComplex & obj); Friend std :: string myPolar (double road, double theta); };
If I do not put const in front of them then they do not work.
const double real (const MyComplex & obj) {back obj .real; }
Other functions are very similar.
announcement
friend const double real (const MyComplex & obj) ;
does not declare a const function, it announces a non-conasible function that gives constant value. Since you return anyway, this is the const
plain useless.
A single const type is declared as:
// double getReal () definition within class;
This creates the underlying parameters for getReal ()
, this
indicator, const
, which gives you Permission is to do this myConstComplex.getReal ()
.
And, as the Deduplicator notes correctly, just litter those friends, you do not need them and you do not want them.
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