python - matplotlib plot_surface plot -

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matplotlib tutorial provides a good example of how to draw a spherical suface:

 
 Code> mpl_toolkits.mplot3d import np as fig plt import numpy as axes3d import matplotlib.pyplot = plt.figure () ax = fig.add_subplot (111, projection = '3d') u = np.linspace ( 0, 2 * np.pi, 100) V = np.linspace (0, np.pi, 100) x = 10 * np.outer (np.cos (u), np.sin (v)) y = 10 * Np.outer (np.sin (u), np.sin (v)) z = 10 * np.outer (np.ones (np.size (u)), np.cos (v) ax.plot_surface (x , Y, z, rstride = 4, cstride = 4, color = 'b') plt.show ()   
 What I understand, it creates a 2D grid for each of the  x ,  y , and  z  of the variable parameters Corresonding with the product  u  and  v . The calculation of the Cartesian coordinates created by the spherical coordinates in the  x ,  y , and  z  variable then  are calculated by U  and < Code> v . 
 
 My question is:  input  why  plot_surface   should be in 2D arrays?  
 
 I think this is something to calculate the normals of the face of each surface, but I can not find it. 
 
 Something like this seems to ask, but the same answer is not particularly enlightened.